20y^2-117y+169=0

Solution for 20y^2-117y+169=0 equation:

20y^2-117y+169=0

a = 20; b = -117; c = +169;
Δ = b2-4ac
Δ = -1172-4·20·169
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-117)-13}{2*20}=\frac{104}{40}
=2+3/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-117)+13}{2*20}=\frac{130}{40}
=3+1/4
$